杰瑞科技汇

Java已启动但为何无后续?

It looks like your sentence got cut off! "Java started but..." is the beginning of a common phrase when describing a problem or an unexpected behavior.

Java已启动但为何无后续?-图1
(图片来源网络,侵删)

Could you please complete the sentence? For example, are you trying to say:

  • "Java started but immediately closed?"
  • "Java started but is very slow?"
  • "Java started but shows an error?"
  • "Java started but the program I'm running doesn't work?"
  • "Java started but I can't run my application?"

To help you effectively, I need more details. Here are some questions to get us started:

What are you trying to do?

  • Run a specific Java application (like a game, a tool, or your own code)?
  • Start a server (like Tomcat or Spring Boot)?
  • Just check if Java is installed and working from the command line?

What exactly happens?

  • Does a command prompt window open and then immediately disappear?
  • Do you see an error message? If so, what does it say? (Please copy and paste the full text).
  • Does the application start but then freeze or crash?

How are you starting it?

  • Are you using a script (.bat, .sh)?
  • Are you running a command directly in the terminal (e.g., java -jar myapp.jar)?
  • Are you double-clicking a file?
  • Are you using an IDE (like IntelliJ, Eclipse, or VS Code)?

Common Scenarios and Solutions

Here are some of the most common "Java started but..." problems and their fixes.

Scenario 1: "Java started but the command prompt window immediately closes."

This is the most common issue. It happens because the program runs, finishes, and the terminal window closes before you can see the output or any errors.

Java已启动但为何无后续?-图2
(图片来源网络,侵删)

Solution: Open a command prompt or terminal, navigate to the directory of your application, and run it manually. This way, the window will stay open and show you any messages.

  • On Windows:

    1. Press Win + R, type cmd, and press Enter.
    2. Use the cd command to go to your application's folder. For example: cd C:\Users\YourUser\Documents\MyJavaApp
    3. Run your application. For example: java -jar MyApplication.jar
  • On macOS / Linux:

    1. Open the Terminal application.
    2. Use the cd command to navigate to your application's folder. For example: cd /home/youruser/myjavaapp
    3. Run your application. For example: java -jar MyApplication.jar

Scenario 2: "Java started but I get an error like 'java' is not recognized as an internal or external command..."

This means your system doesn't know where the Java executable (java.exe) is located.

Solution: You need to add Java's bin directory to your system's PATH environment variable.

  • On Windows 10/11:

    1. Search for "Environment Variables" and open "Edit the system environment variables".
    2. Click the "Environment Variables..." button.
    3. In the "System variables" section, find and select the Path variable, then click "Edit...".
    4. Click "New" and add the path to your Java bin directory (e.g., C:\Program Files\Java\jdk-17.0.2\bin).
    5. Click OK on all windows and restart your command prompt.
  • On macOS / Linux:

    1. Find your Java home directory by running: /usr/libexec/java_home -V
    2. Edit your shell profile file (e.g., ~/.zshrc for macOS Catalina and later, or ~/.bash_profile for older systems).
    3. Add the following line, replacing [JAVA_HOME_PATH] with the path from the previous step:
      export PATH="$JAVA_HOME/bin:$PATH"
    4. Save the file and restart your terminal or run source ~/.zshrc.

Scenario 3: "Java started but I get a Could not find or load main class error."

This means the Java Virtual Machine (JVM) can't locate the class you're trying to run.

Solution: This is usually a classpath issue. The JVM needs to know where to find your compiled .class files.

  • If you're running a .jar file: Make sure you are using the -jar flag correctly. The main class must be specified correctly within the JAR's manifest file.
    java -jar my-application.jar
  • If you're running a class file: You need to tell Java where the class file is located using the -cp (classpath) flag.
    # Syntax: java -cp [path_to_classes] [fully.qualified.ClassName]
    java -cp . com.example.MyMainClass

    The means "the current directory". If your class is in a package, you must use the full package name.

Please provide more details, and I can give you a more specific answer

分享:
扫描分享到社交APP
上一篇
下一篇