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Python KeyError 33,如何解决这个键错误?

Of course! A KeyError: 33 in Python is a very common error. Let's break down exactly what it means, why it happens, and how to fix it with clear examples.

Python KeyError 33,如何解决这个键错误?-图1
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The Short Answer: What it Means

A KeyError: 33 means you tried to access an element in a dictionary using a key (33) that does not exist in that dictionary.

Think of a Python dictionary like a real-world dictionary.

  • The keys are the words you look up (e.g., "apple").
  • The values are the definitions for those words (e.g., "a fruit").

If you try to look up the definition for the word "xylophone" but your dictionary only has words from A to M, you won't find it. The Python equivalent of this is a KeyError.

In your case, the "word" you were looking for was the number 33, and it wasn't in your "dictionary."

Python KeyError 33,如何解决这个键错误?-图2
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The Core Problem: Accessing a Non-Existent Key

The error is raised when you use square bracket notation [] to get an item from a dictionary.

# Our sample dictionary
student_grades = {
    "Alice": 92,
    "Bob": 88,
    "Charlie": 95
}
# This will work fine
print(student_grades["Alice"])  # Output: 92
# This will cause a KeyError: 'David'
# print(student_grades["David"]) 
# This will cause a KeyError: 33
# Let's say we have a dictionary where keys are numbers
product_prices = {
    101: 19.99,
    102: 5.50,
    105: 250.00
}
# This will cause the error you're seeing
print(product_prices[33]) 

Running the last line print(product_prices[33]) will produce:

Traceback (most recent call last):
  File "your_script.py", line 14, in <module>
    print(product_prices[33])
KeyError: 33

Common Causes and How to Fix Them

Here are the most common scenarios that lead to this error and the best ways to handle them.

Solution 1: Check if the Key Exists First (The in keyword)

Before trying to access a key, you can check if it's in the dictionary. This is the most straightforward way to prevent the error.

Python KeyError 33,如何解决这个键错误?-图3
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product_prices = {101: 19.99, 102: 5.50, 105: 250.00}
key_to_find = 33
if key_to_find in product_prices:
    print(f"The price for product {key_to_find} is {product_prices[key_to_find]}")
else:
    print(f"Sorry, product {key_to_find} was not found.")

Output:

Sorry, product 33 was not found.

Solution 2: Use the .get() Method (Recommended)

The dictionary .get() method is the most "Pythonic" and safest way to access values. It does two things:

  1. If the key exists, it returns the corresponding value.
  2. If the key does not exist, it returns None (or a default value you specify) instead of raising an error.
product_prices = {101: 19.99, 102: 5.50, 105: 250.00}
key_to_find = 33
# Using .get() with no default value
price = product_prices.get(key_to_find)
print(f"The price is: {price}") # Output: The price is: None
# Using .get() with a default value
price = product_prices.get(key_to_find, "Product not found")
print(f"The price is: {price}") # Output: The price is: Product not found

Solution 3: Use a try...except Block

This is useful when the key should be there, and its absence indicates a more serious problem in your program's logic. You "try" the operation and "catch" the error if it occurs.

product_prices = {101: 19.99, 102: 5.50, 105: 250.00}
key_to_find = 33
try:
    price = product_prices[key_to_find]
    print(f"The price for product {key_to_find} is {price}")
except KeyError:
    print(f"Error: Product ID {key_to_find} is not in our database.")

Output:

Error: Product ID 33 is not in our database.

Other Data Structures That Can Raise a KeyError

While dictionaries are the most common cause, other data structures can also raise this error.

Pandas DataFrame

When using the Pandas library, a KeyError often means you tried to access a column that doesn't exist.

import pandas as pd
data = {'Name': ['Alice', 'Bob'], 'Age': [25, 30]}
df = pd.DataFrame(data)
# This will raise a KeyError: 'City'
# print(df['City'])
# Correct way to check for columns
if 'City' in df.columns:
    print(df['City'])
else:
    print("The 'City' column does not exist.")

JSON Data

JSON objects behave very similar to Python dictionaries.

import json
config_json = '{"host": "localhost", "port": 8080}'
config = json.loads(config_json)
# This will raise a KeyError: 'user'
# print(config['user'])
# Use .get() for safety
username = config.get('user', 'default_user')
print(f"Username: {username}") # Output: Username: default_user

Debugging Checklist: How to Find Your KeyError

  1. Identify the Line: Look at the traceback. It will tell you the exact file and line number where the error occurred.
  2. Find the Dictionary: Look at the variable on the left side of the square brackets (e.g., my_dict[33]). What is the name of that dictionary?
  3. Print the Dictionary: Add a print() statement right before the error line to see what keys are actually in the dictionary.
    # ... code before the error ...
    print(f"Available keys in product_prices are: {list(product_prices.keys())}")
    print(product_prices[33]) # Your error line

    This will output something like Available keys in product_prices are: [101, 102, 105], making it obvious that 33 is missing.

  4. Check for Typos: Is the key you're using (33) exactly the same as the key in the dictionary? A typo like "33" (a string instead of a number) would also cause a KeyError.
  5. Check the Data Type: Keys in dictionaries are case-sensitive and type-sensitive. 33 (an integer) is different from "33" (a string).
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